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Question about pinto genetics

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        10-20-2013, 12:12 AM
      #11
    Started
    ^^^Except for Little Joe Cartwright, who rode pintos. : )
    JCnGrace likes this.
         
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        10-20-2013, 12:19 AM
      #12
    Yearling
    Thank you Sunandbeach.
         
        10-20-2013, 01:35 AM
      #13
    Green Broke
    Quote:
    Originally Posted by Tryst    
    ^^^^ this

    Tobiano, splash, frame, sabino, black, cream, agouti, etc are each on their own loci. Each parent will pass a gene from each loci, so a horse can carry multiple patterns, and could, in theory, be homozygous for all of them.
    Just touching on this. Tobiano and the only currently testable sabino are located on the same locus, so they cannot be homozygous for one and carry genes of the other. Also on this locus is roan and all of the currently testable dominant whites. I imagine the other forms of sabino and dominant white that aren't currently testable would be here too, and I would not be surprised if it turns out rabicano is too.
         
        10-20-2013, 09:51 AM
      #14
    Trained
    True roan is also on the same locus as tibia of as well. A horse that is to animal and roan is automatically heterozygous for both patterns.
    Chiilaa likes this.
         
        10-20-2013, 11:01 AM
      #15
    Green Broke
    Quote:
    Originally Posted by NdAppy    
    True roan is also on the same locus as tibia of as well. A horse that is to animal and roan is automatically heterozygous for both patterns.
    I love your autocorrect so much
         
        10-20-2013, 11:06 AM
      #16
    Trained
    *facepalm* That's what I get for trying to post from my iPad.

    It should say -
    True roan is also on the same locus as tobiano as well. A horse that is tobiano and roan is automatically heterozygous for both patterns.

    *sigh* Remind me just to read from my iPad and not post anymore.
    Chiilaa likes this.
         
        10-20-2013, 11:28 AM
      #17
    Trained
    To the OP regarding passing on the black gene...

    All horses are one of two base colors: red (ee) and black (EE or Ee). Then there are modifiers on top of that. In the case of your mare, she carries the brown form of the agouti gene (AtAt or Atat). There's also the bay form of the agouti gene (AA or Aa) and the wild bay form of the agouti gene (not sure the genetic designation for that one). So, your mare, being brown, would have to be EEAtAt, EEAtat, EeAtAt, or EeAtat. In order to produce a bay foal (if the foal was truly bay and not brown), the sire would have to carry bay agouti (AA or Aa). However, since agouti restricts the expression of black to the hard points of the horse and being a red-based horse, the sire wouldn't have any black to restrict, his agouti status would only be known through testing.

    NdAppy and Chiila, that brings a related question to mind. Can a horse carry more than one form of agouti? For example, if the OP's mare is homozygous for brown could she be heterozygous for regular bay as well. Or are they mutually exclusive? I think I know the answer, but I'm still curious.
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        10-20-2013, 11:30 AM
      #18
    Trained
    A horse can be AA, AAt, AtAt, AtA+, AA+, A+A+, (A+ is wild bay, not testable) but cannot be homozygous for one form and still carry another
         
        10-20-2013, 11:56 AM
      #19
    Trained
    Ah, ok! That makes sense. Thanks, NdAppy!
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        10-20-2013, 12:57 PM
      #20
    Yearling
    Thanks Drafty. Those agouti designations always confused the heck out of me back when I was doing research because I could never find a good source that put it in laymen's terms.

    Nd, Drafty asked about being homozygous for brown, but can a horse be heterozygous for brown and heterozygous for bay (is this the AAt agouti?) and which color would be dominant?

    I want to thank everyone for their input on this thread. It's fascinating and I'm even starting to get some of it through my thick skull. Keep up the discussions!
         

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